An Armstrong number is a number(narcissistic number) equal to the sum of its own digits raised to the power of the number of digits. Here’s an example of how you can check if a number is an Armstrong number in Java:

import java.util.Scanner;

public class ArmstrongNumber {

    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);

        System.out.print(“Enter a number: “);

        int number = scanner.nextInt();

        if (isArmstrong(number)) {

            System.out.println(number + ” is an Armstrong number.”);

        } else {

            System.out.println(number + ” is not an Armstrong number.”);

        }

    }

    public static boolean isArmstrong(int number) {

        int originalNumber = number;

        int numDigits = String.valueOf(number).length();

        int sum = 0;

        while (number != 0) {

            int digit = number % 10;

            sum += Math.pow(digit, numDigits);

            number /= 10;

        }

        return sum == originalNumber;

    }

}

In this code, the first user enters a number. Then, we call the isArmstrong() method to check if the entered number is an Armstrong number. The isArmstrong() method calculates the sum of each digit raised to the power of the number of digits and checks if it equals the original number.

You can run this code, enter a number, and it will tell you whether the number is an Armstrong number or not.

Armstrong number is that number which of three integer digits, which sum of the cube

of its individual digits(like 13+53+33) is equal (=)to that number which we enter like 153, the cube of 1 and the cube of 5, and the cube of 3 and the sum of both (1*1*1)+(5*5*5)+(3*3*3)=153 means its Armstrong number.

others are…..370,371,407 etc

Armstrong Number Example in Java

class arm

{

public static void main(String aa[])

{

int number,sum=0,temp,remainder;

number=Integer.parseInt(aa[0]);  //number enter by user(run time0

temp=number;    //value assign to variable temp

while(temp!=0)    //condition check if temp is not equal 0 then

{

remainder=temp%10;   //show  remainder

sum=sum+remainder*remainder*remainder;  //calculation

temp=temp/10;  

}

if(number==sum)   //if  the value of the number and the sum are equal then Armstrong

System.out.print(“armstrong”);

else

System.out.print(“not”);

}}

Explanation…

In the above example, we enter the value(integer type). If the value is not equal to zero then the

calculation will start. After analysis it checks the output if the number and the sum are equal then

the result will be Armstrong otherwise not.